This question was previously asked in

RPSC ME Lecturer 2014: Official Paper

- Half of average velocity
- Two-third of average velocity
- Twice of average velocity
- Equal to average velocity

Option 3 : Twice of average velocity

Free

SSC JE ME Full Test 4

5572

200 Questions
200 Marks
120 Mins

__Explanation:__

For a fully developed laminar viscous flow through a circular pipe, the maximum velocity is equal to twice the average velocity.

i.e. \({U_{max}} = 2 \times {U_{avg}}\)

\({U_{max}} = \frac{1}{{4\mu }}\left( { - \frac{{\partial P}}{{\partial x}}} \right).{R^2}\)

\(U_{avg}=\bar U = \frac{1}{{8\mu }}\left( { - \frac{{\partial P}}{{\partial x}}} \right).{R^2}\)

Hence \(\frac{{{U_{max}}}}{{\bar U}} = 2\)

For the fully developed laminar flow through the parallel plates, the maximum velocity is equal to the (3/2) times of the average velocity.

i.e. \({U_{max}} = \frac{3}{2} \times {U_{avg}}\)

India’s **#1 Learning** Platform

Start Complete Exam Preparation

Daily Live MasterClasses

Practice Question Bank

Mock Tests & Quizzes

Trusted by 2,17,83,996+ Students

Testbook Edu Solutions Pvt. Ltd.

1st & 2nd Floor, Zion Building,

Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

[email protected]
Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

Toll Free:1800 833 0800

Office Hours: 10 AM to 7 PM (all 7 days)